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大数乘法,大数加法,大数减法

发布时间:2021-02-25 02:02:56 所属栏目:大数据 来源:网络整理
导读:#include iostream #include cstring using namespace std ; class MData { private : int n , m ; char * str1 ,* str2 ; public : char * mul (); //乘法 char * add (); //加法 char * sub (); //减法 char * div (); //除法 MData (); MData ( const cha

#include <iostream>

#include<cstring>
using namespace std;
 
class MData
{
 private:
    int n,m;
    char *str1,*str2;
 public:
    char *mul();//乘法
    char *add();//加法
    char *sub();//减法
    char *div();//除法
    MData();
    MData(const char *s1,const char * s2);
    void init(const char *s1,const char * s2);
    ~MData();
 
};
 
MData::MData()
{
    str1=nullptr;
    str2 = nullptr;
    n = 0;
    m = 0;
}
MData::MData(const char *s1, const char *s2)
{
    n = (int)strlen(s1);
    m = (int)strlen(s2);
    str1 = new char[n+1]{''};
    str2 = new char[m+1]{''};
    strcpy(this->str1,s1);
    strcpy(this->str2,s2);
}
void MData::init(const char *s1,s2);
}
MData::~MData()
{
    if(str1!=nullptr)
        delete[] str1;
    if(str2!=nullptr)
        delete[] str2;
}
char* MData::mul()//乘法
{
    int *s = new int[n+m];
    memset(s,0,sizeof(int)*(n+m));
    for(int i = 0;i<n;i++)
        for(int k = 0;k<m;k++)
        {
            s[i+k+1] += (str1[i]-'0')*(str2[k]-'0');
        }
    for(int i = n+m-1;i>=0;i--)
    {
        if(s[i]>=10)
        {
            s[i-1] += s[i]/10;
            s[i] %= 10;
        }
    }
    int i = 0;
    while(s[i] == 0)
    {
        i++;
        if(i == n+m)
            return "0";
    }
    char *sum = new char[n+m-i+1]{''};
    int k = 0;
    int kn = n+m-i+1;
    for(;k<kn&&i<n+m;k++,i++)
    {
        sum[k] = s[i]+'0';
    }
    sum[k] = '';
    delete[] s;
    return sum;
}
 
char *MData::add()//加法
{
    int *s,temp;
    if(n > m)
    {
         temp = n;
         s = new int[n+1];
         memset(s,sizeof(int)*(n+1));
         for(int i = 0;i<n;i++)
         {
             if(i >= n-m)
                s[i+1] = (str1[i]-'0')+(str2[i-(n-m)]-'0');
             else
                 s[i+1] = str1[i]-'0';
         }
    }
    else
    {
        temp = m;
        s = new int[m+1];
        memset(s,sizeof(int)*(m+1));
        for(int i = 0;i<m;i++)
        {
            if(i >= m-n)
               s[i+1] = (str2[i]-'0')+(str1[i-(m-n)]-'0');
            else
                s[i+1] = str2[i]-'0';
        }
    }
    for(int i = temp;i>=0;i--)
    {
        if(s[i]>=10)
        {
            s[i-1] += s[i]/10;
            s[i] %= 10;
        }
    }
    int i = 0;
    while(s[i] == 0)
    {
        i++;
        if(i == temp+1)
            return "0";
    }
    char *sum = new char[(temp+1)-i+1]{''};
    int k = 0;
    int kn = (temp+1)-i+1;
    for(;k<kn&&i<temp+1;k++,i++)
    {
        sum[k] = s[i]+'0';
    }
    sum[k] = '';
    delete[] s;
    return sum;
}
 
char *MData::sub()
{
    int *s,temp;
    bool bt = false;
    if(n >= m)
    {
        s = new int[n+1];
        temp = n;
        memset(s,sizeof(int)*(n+1));
        if(n > m)
        {
            for(int i = 0;i < n;i++)
            {
                if(i >= n-m)
                    s[i+1] = (str1[i]-'0')-(str2[i-(n-m)]-'0');
                else
                    s[i+1] = str1[i]-'0';
            }
        }
        else
        {
            if(strcmp(str1,str2)>0)
            {
                for(int i = 0;i < n;i++)
                {
                    s[i+1] = (str1[i]-'0')-(str2[i]-'0');
                }
            }
            else
            {
                bt = true;
                for(int i = 0;i < n;i++)
                {
                    s[i+1] = (str2[i]-'0')-(str1[i]-'0');
                }
            }
        }
    }
    else
    {
        bt = true;
        s= new int[m+1];
        temp = m;
        memset(s,sizeof(int)*(m+1));
        for(int i = 0;i<m;i++)
        {
            if(i >= m-n)
                s[i+1] = (str2[i]-'0')-(str1[i-(m-n)]-'0');
            else
                s[i+1] = str2[i]-'0';
        }
    }
    for(int i = temp;i>=0;i--)
    {
        if(s[i] < 0)
        {
            s[i-1] -= 1;
            s[i] += 10;
        }
    }
    int i = 0;
    while(s[i] == 0)
    {
        i++;
        if(i == n+1)
        {
            return "0";
        }
    }
    char *sum;
    if(bt)
    {
        sum = new char[(temp+1)-(i-1)+1]{''};
        int k = 0;
        int kn = (temp+1)-i+1;
        for(;k<kn&&i<temp+1;k++,i++)
        {
           if(k == 0)
               sum[k] = '-';
           sum[k+1] = s[i]+'0';
        }
        sum[k+1] = '';
    }
    else
    {
        sum = new char[(temp+1)-i+1]{''};
        int k = 0;
        int kn = (temp+1)-i+1;
        for(;k<kn&&i<temp+1;k++,i++)
        {
           sum[k] = s[i]+'0';
        }
        sum[k] = '';
    }
    delete[] s;
    return sum;
}
 
char *MData::div()
{
    if(n < m)
        return "0";
    else
    {
        if(n == m)
        {
            if(strcmp(str1,str2) < 0)
                return "0";
            else
            {
                int i = 0;
                char *st = this->sub();
                while(st[0]!='-')
                {
                    i++;
                    strcpy(str1,st);
                    st = this->sub();
                }
                char *str = new char[2]{0};
                str[0] = i+'0';
                str[1] = '';
                return str;
            }
        }
        else
        {
            int *s = new int[n];
            for(int i = 0;i<n;i++)
                s[i] = 0;
            int i = 0;
            char *str = new char[m]{0};
            str = strncpy(str,str1,1);
            str[1] = '';
            char *tp = str1+1;
            char *temp = str1;
            str1 = str;
            while(i<n)
            {
                if(strlen(str1) < m ||
                        (strcmp(str1,str2)<0 && strlen(str1) == m))
                {
                    strncpy(str,tp,1);
                    str[1] = '';
                    str1 = strcat(str1,str);
                    tp++;
                    i++;
                }
                else
                {
                    s[i]++;
                    str1 = this->sub();
                }
                if(i == n)
                {
                    break;
                }
            }
            for(int mm = n-1;mm >= 0;mm--)
            {
                if(s[mm] >= 10)
                {
                    s[mm-1] += s[mm]/10;
                    s[mm] %= 10;
                }
            }
            int nn = 0;
            while(s[nn] == 0)
            {
                nn++;
                if(nn == n)
                    return "0";
            }
            char *strchar = new char[n+1 -nn];
            memset(strchar,sizeof(char)*(n+1-nn));
            int k = 0;
            for(;k<n && nn < n;k++,nn++)
            {
                strchar[k] = s[nn]+'0';
            }
            strchar[k] = '';
            delete[] temp;
            return strchar;
        }
    }
}
int main()
{
    int i = 0;
    while(i<100)
    {
        i++;
        char *str1=new char[10000]{''},*str2=new char[10000]{''};
        cin>>str1;
        cin>>str2;
        MData sk(str1,str2);
        char *mul = sk.mul();//乘法
        cout << "1:"<< mul << endl;
        char *add = sk.add();//加法
        cout<<"2:" << add<<endl;
        char *sub = sk.sub();//减法
        cout<<"3:"<< sub <<endl;
        //char *div = sk.div();//除法
        //cout<<"4:"<<div<<endl<<endl;
        if(i == 100)
        {
            delete[]str1;
            delete[]str2;
        }
    }
 
    return 0;
}
大数除法还有问题,没有时间去完善,如果你完善了,请评论并回复代码哈,谢谢了

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